11302213300121 has 2 divisors, whose sum is σ = 11302213300122. Its totient is φ = 11302213300120.

The previous prime is 11302213300111. The next prime is 11302213300123. The reversal of 11302213300121 is 12100331220311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11029871265625 + 272342034496 = 3321125^2 + 521864^2 .

It is an emirp because it is prime and its reverse (12100331220311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11302213300121 - 2¹⁸ = 11302213037977 is a prime.

It is a super-3 number, since 3×11302213300121³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 11302213300123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11302213300093 and 11302213300102.

It is not a weakly prime, because it can be changed into another prime (11302213300123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651106650060 + 5651106650061.

It is an arithmetic number, because the mean of its divisors is an integer number (5651106650061).

Almost surely, 2^{11302213300121} is an apocalyptic number.

It is an amenable number.

11302213300121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11302213300121 is an equidigital number, since it uses as much as digits as its factorization.

11302213300121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 11302213300121 its reverse (12100331220311), we get a palindrome (23402544520432).

The spelling of 11302213300121 in words is "eleven trillion, three hundred two billion, two hundred thirteen million, three hundred thousand, one hundred twenty-one".