1130233243457 has 2 divisors, whose sum is σ = 1130233243458. Its totient is φ = 1130233243456.

The previous prime is 1130233243421. The next prime is 1130233243459. The reversal of 1130233243457 is 7543423320311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1113455481616 + 16777761841 = 1055204^2 + 129529^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130233243457 - 2⁸ = 1130233243201 is a prime.

Together with 1130233243459, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1130233243457.

It is not a weakly prime, because it can be changed into another prime (1130233243459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565116621728 + 565116621729.

It is an arithmetic number, because the mean of its divisors is an integer number (565116621729).

Almost surely, 2^{1130233243457} is an apocalyptic number.

It is an amenable number.

1130233243457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130233243457 is an equidigital number, since it uses as much as digits as its factorization.

1130233243457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 38.

Adding to 1130233243457 its reverse (7543423320311), we get a palindrome (8673656563768).

The spelling of 1130233243457 in words is "one trillion, one hundred thirty billion, two hundred thirty-three million, two hundred forty-three thousand, four hundred fifty-seven".