Base | Representation |
---|---|
bin | 10101000011011011… |
… | …11101011100110111 |
3 | 1002011201210201020021 |
4 | 22201231331130313 |
5 | 141122044131201 |
6 | 5105332550011 |
7 | 550046613511 |
oct | 124155753467 |
9 | 32151721207 |
10 | 11303114551 |
11 | 488034a293 |
12 | 2235482307 |
13 | 10b1975c81 |
14 | 793254bb1 |
15 | 4624b5ea1 |
hex | 2a1b7d737 |
11303114551 has 2 divisors, whose sum is σ = 11303114552. Its totient is φ = 11303114550.
The previous prime is 11303114477. The next prime is 11303114609. The reversal of 11303114551 is 15541130311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11303114551 - 211 = 11303112503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11303174551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651557275 + 5651557276.
It is an arithmetic number, because the mean of its divisors is an integer number (5651557276).
Almost surely, 211303114551 is an apocalyptic number.
11303114551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303114551 is an equidigital number, since it uses as much as digits as its factorization.
11303114551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 11303114551 its reverse (15541130311), we get a palindrome (26844244862).
The spelling of 11303114551 in words is "eleven billion, three hundred three million, one hundred fourteen thousand, five hundred fifty-one".
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