Base | Representation |
---|---|
bin | 10101000011100010… |
… | …11011101001111111 |
3 | 1002011210111221201121 |
4 | 22201301123221333 |
5 | 141122312242303 |
6 | 5105404251411 |
7 | 550060424146 |
oct | 124161335177 |
9 | 32153457647 |
10 | 11304024703 |
11 | 4880911084 |
12 | 2235840b67 |
13 | 10b1c0431a |
14 | 79341075d |
15 | 4625e59bd |
hex | 2a1c5ba7f |
11304024703 has 2 divisors, whose sum is σ = 11304024704. Its totient is φ = 11304024702.
The previous prime is 11304024691. The next prime is 11304024707. The reversal of 11304024703 is 30742040311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11304024703 is a prime.
It is a super-3 number, since 3×113040247033 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304024707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652012351 + 5652012352.
It is an arithmetic number, because the mean of its divisors is an integer number (5652012352).
Almost surely, 211304024703 is an apocalyptic number.
11304024703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304024703 is an equidigital number, since it uses as much as digits as its factorization.
11304024703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 11304024703 in words is "eleven billion, three hundred four million, twenty-four thousand, seven hundred three".
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