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1130424413147 is a prime number
BaseRepresentation
bin10000011100110010100…
…010111010101111011011
311000001211012222002111022
4100130302202322233123
5122010102122210042
62223150530153055
7144445653654341
oct20346242725733
94001735862438
101130424413147
113a6457124997
12163100a2278b
13827a207b9c3
143c9da02d991
151e6119b1cd2
hex107328babdb

1130424413147 has 2 divisors, whose sum is σ = 1130424413148. Its totient is φ = 1130424413146.

The previous prime is 1130424413093. The next prime is 1130424413201. The reversal of 1130424413147 is 7413144240311.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1130424413093) and next prime (1130424413201).

It is a cyclic number.

It is not a de Polignac number, because 1130424413147 - 226 = 1130357304283 is a prime.

It is a super-3 number, since 3×11304244131473 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1130424410147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565212206573 + 565212206574.

It is an arithmetic number, because the mean of its divisors is an integer number (565212206574).

Almost surely, 21130424413147 is an apocalyptic number.

1130424413147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130424413147 is an equidigital number, since it uses as much as digits as its factorization.

1130424413147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 1130424413147 its reverse (7413144240311), we get a palindrome (8543568653458).

The spelling of 1130424413147 in words is "one trillion, one hundred thirty billion, four hundred twenty-four million, four hundred thirteen thousand, one hundred forty-seven".