Base | Representation |
---|---|
bin | 1010010001111111110011… |
… | …1010000001001010000111 |
3 | 1111000200101020121010120221 |
4 | 2210133330322001022013 |
5 | 2440202202304221203 |
6 | 40013042532005211 |
7 | 2244465066536662 |
oct | 244377472011207 |
9 | 44020336533527 |
10 | 11304302023303 |
11 | 3669144875a73 |
12 | 1326a23a60807 |
13 | 63ccb6600083 |
14 | 2b11b9baa6d9 |
15 | 1490b689babd |
hex | a47fce81287 |
11304302023303 has 2 divisors, whose sum is σ = 11304302023304. Its totient is φ = 11304302023302.
The previous prime is 11304302023283. The next prime is 11304302023331. The reversal of 11304302023303 is 30332020340311.
11304302023303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11304302023303 is a prime.
It is a super-3 number, since 3×113043020233033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304302023603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652151011651 + 5652151011652.
It is an arithmetic number, because the mean of its divisors is an integer number (5652151011652).
Almost surely, 211304302023303 is an apocalyptic number.
11304302023303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304302023303 is an equidigital number, since it uses as much as digits as its factorization.
11304302023303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 11304302023303 its reverse (30332020340311), we get a palindrome (41636322363614).
The spelling of 11304302023303 in words is "eleven trillion, three hundred four billion, three hundred two million, twenty-three thousand, three hundred three".
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