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1130433104041 is a prime number
BaseRepresentation
bin10000011100110011000…
…100000100100010101001
311000001211211022122011021
4100130303010010202221
5122010111333312131
62223151440332441
7144446120562253
oct20346304044251
94001754278137
101130433104041
113a646102054a
12163103914121
13827a3b02747
143c9db252cd3
151e61262be11
hex107331048a9

1130433104041 has 2 divisors, whose sum is σ = 1130433104042. Its totient is φ = 1130433104040.

The previous prime is 1130433103999. The next prime is 1130433104063. The reversal of 1130433104041 is 1404013340311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 605719758400 + 524713345641 = 778280^2 + 724371^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130433104041 - 27 = 1130433103913 is a prime.

It is a super-3 number, since 3×11304331040413 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1130433103997 and 1130433104015.

It is not a weakly prime, because it can be changed into another prime (1130433194041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565216552020 + 565216552021.

It is an arithmetic number, because the mean of its divisors is an integer number (565216552021).

Almost surely, 21130433104041 is an apocalyptic number.

It is an amenable number.

1130433104041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130433104041 is an equidigital number, since it uses as much as digits as its factorization.

1130433104041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1130433104041 its reverse (1404013340311), we get a palindrome (2534446444352).

The spelling of 1130433104041 in words is "one trillion, one hundred thirty billion, four hundred thirty-three million, one hundred four thousand, forty-one".