11304421321 has 2 divisors, whose sum is σ = 11304421322. Its totient is φ = 11304421320.

The previous prime is 11304421319. The next prime is 11304421327. The reversal of 11304421321 is 12312440311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8108102025 + 3196319296 = 90045^2 + 56536^2 .

It is a cyclic number.

It is not a de Polignac number, because 11304421321 - 2¹ = 11304421319 is a prime.

It is a super-3 number, since 3×11304421321³ (a number of 31 digits) contains 333 as substring.

Together with 11304421319, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11304421292 and 11304421301.

It is not a weakly prime, because it can be changed into another prime (11304421327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652210660 + 5652210661.

It is an arithmetic number, because the mean of its divisors is an integer number (5652210661).

Almost surely, 2^11304421321 is an apocalyptic number.

It is an amenable number.

11304421321 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304421321 is an equidigital number, since it uses as much as digits as its factorization.

11304421321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 11304421321 its reverse (12312440311), we get a palindrome (23616861632).

The spelling of 11304421321 in words is "eleven billion, three hundred four million, four hundred twenty-one thousand, three hundred twenty-one".