Base | Representation |
---|---|
bin | 10101000011100101… |
… | …11100011111001111 |
3 | 1002011211021002210101 |
4 | 22201302330133033 |
5 | 141122412440302 |
6 | 5105420551531 |
7 | 550063665403 |
oct | 124162743717 |
9 | 32154232711 |
10 | 11304421327 |
11 | 4881062071 |
12 | 22359b25a7 |
13 | 10b2012a04 |
14 | 7934b5103 |
15 | 462673287 |
hex | 2a1cbc7cf |
11304421327 has 2 divisors, whose sum is σ = 11304421328. Its totient is φ = 11304421326.
The previous prime is 11304421321. The next prime is 11304421367. The reversal of 11304421327 is 72312440311.
It is a weak prime.
It is an emirp because it is prime and its reverse (72312440311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11304421327 - 23 = 11304421319 is a prime.
It is a super-3 number, since 3×113044213273 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11304421295 and 11304421304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304421321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652210663 + 5652210664.
It is an arithmetic number, because the mean of its divisors is an integer number (5652210664).
Almost surely, 211304421327 is an apocalyptic number.
11304421327 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304421327 is an equidigital number, since it uses as much as digits as its factorization.
11304421327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 11304421327 its reverse (72312440311), we get a palindrome (83616861638).
The spelling of 11304421327 in words is "eleven billion, three hundred four million, four hundred twenty-one thousand, three hundred twenty-seven".
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