Base | Representation |
---|---|
bin | 10101000011100101… |
… | …11101100101001000 |
3 | 1002011211021022221001 |
4 | 22201302331211020 |
5 | 141122413111200 |
6 | 5105421024344 |
7 | 550064014423 |
oct | 124162754510 |
9 | 32154238831 |
10 | 11304425800 |
11 | 4881065468 |
12 | 22359b50b4 |
13 | 10b2014a65 |
14 | 7934b69ba |
15 | 46267476a |
hex | 2a1cbd948 |
11304425800 has 24 divisors (see below), whose sum is σ = 26282790450. Its totient is φ = 4521770240.
The previous prime is 11304425761. The next prime is 11304425813. The reversal of 11304425800 is 852440311.
It can be written as a sum of positive squares in 3 ways, for example, as 6183305956 + 5121119844 = 78634^2 + 71562^2 .
It is a super-3 number, since 3×113044258003 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28260865 + ... + 28261264.
Almost surely, 211304425800 is an apocalyptic number.
11304425800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11304425800 is an abundant number, since it is smaller than the sum of its proper divisors (14978364650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11304425800 is a wasteful number, since it uses less digits than its factorization.
11304425800 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56522145 (or 56522136 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 28.
The spelling of 11304425800 in words is "eleven billion, three hundred four million, four hundred twenty-five thousand, eight hundred".
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