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11304431113999 is a prime number
BaseRepresentation
bin1010010010000000010010…
…0110011101011100001111
31111000200201020111121201211
42210200010212131130033
52440202433331121444
640013103422515251
72244501225022462
oct244400446353417
944020636447654
1011304431113999
1136692007267a1
121326a5b135b27
1364000728a9ba
142b11ccdb12d9
151490c2d9ac34
hexa480499d70f

11304431113999 has 2 divisors, whose sum is σ = 11304431114000. Its totient is φ = 11304431113998.

The previous prime is 11304431113981. The next prime is 11304431114047. The reversal of 11304431113999 is 99931113440311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11304431113999 - 25 = 11304431113967 is a prime.

It is a super-3 number, since 3×113044311139993 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11304431713999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652215556999 + 5652215557000.

It is an arithmetic number, because the mean of its divisors is an integer number (5652215557000).

Almost surely, 211304431113999 is an apocalyptic number.

11304431113999 is a deficient number, since it is larger than the sum of its proper divisors (1).

11304431113999 is an equidigital number, since it uses as much as digits as its factorization.

11304431113999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 314928, while the sum is 49.

The spelling of 11304431113999 in words is "eleven trillion, three hundred four billion, four hundred thirty-one million, one hundred thirteen thousand, nine hundred ninety-nine".