Base | Representation |
---|---|
bin | 1010010010000000010010… |
… | …0110011101011100001111 |
3 | 1111000200201020111121201211 |
4 | 2210200010212131130033 |
5 | 2440202433331121444 |
6 | 40013103422515251 |
7 | 2244501225022462 |
oct | 244400446353417 |
9 | 44020636447654 |
10 | 11304431113999 |
11 | 36692007267a1 |
12 | 1326a5b135b27 |
13 | 64000728a9ba |
14 | 2b11ccdb12d9 |
15 | 1490c2d9ac34 |
hex | a480499d70f |
11304431113999 has 2 divisors, whose sum is σ = 11304431114000. Its totient is φ = 11304431113998.
The previous prime is 11304431113981. The next prime is 11304431114047. The reversal of 11304431113999 is 99931113440311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11304431113999 - 25 = 11304431113967 is a prime.
It is a super-3 number, since 3×113044311139993 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304431713999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652215556999 + 5652215557000.
It is an arithmetic number, because the mean of its divisors is an integer number (5652215557000).
Almost surely, 211304431113999 is an apocalyptic number.
11304431113999 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304431113999 is an equidigital number, since it uses as much as digits as its factorization.
11304431113999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 314928, while the sum is 49.
The spelling of 11304431113999 in words is "eleven trillion, three hundred four billion, four hundred thirty-one million, one hundred thirteen thousand, nine hundred ninety-nine".
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