Base | Representation |
---|---|
bin | 1010010010000000010010… |
… | …0110011101011100111111 |
3 | 1111000200201020111121210121 |
4 | 2210200010212131130333 |
5 | 2440202433331122142 |
6 | 40013103422515411 |
7 | 2244501225022561 |
oct | 244400446353477 |
9 | 44020636447717 |
10 | 11304431114047 |
11 | 3669200726835 |
12 | 1326a5b135b67 |
13 | 64000728aa26 |
14 | 2b11ccdb1331 |
15 | 1490c2d9ac67 |
hex | a480499d73f |
11304431114047 has 2 divisors, whose sum is σ = 11304431114048. Its totient is φ = 11304431114046.
The previous prime is 11304431113999. The next prime is 11304431114111. The reversal of 11304431114047 is 74041113440311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11304431114047 is a prime.
It is a super-3 number, since 3×113044311140473 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11304431114947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5652215557023 + 5652215557024.
It is an arithmetic number, because the mean of its divisors is an integer number (5652215557024).
Almost surely, 211304431114047 is an apocalyptic number.
11304431114047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11304431114047 is an equidigital number, since it uses as much as digits as its factorization.
11304431114047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 11304431114047 its reverse (74041113440311), we get a palindrome (85345544554358).
The spelling of 11304431114047 in words is "eleven trillion, three hundred four billion, four hundred thirty-one million, one hundred fourteen thousand, forty-seven".
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