Base | Representation |
---|---|
bin | 10000011100110110101… |
… | …110000011010000001101 |
3 | 11000002000002201211220112 |
4 | 100130312232003100031 |
5 | 122010223034043321 |
6 | 2223201511125405 |
7 | 144450464123531 |
oct | 20346656032015 |
9 | 4002002654815 |
10 | 1130494440461 |
11 | 3a6492704501 |
12 | 163120373865 |
13 | 827b3729a99 |
14 | 3ca0545bbc1 |
15 | 1e617be5a5b |
hex | 10736b8340d |
1130494440461 has 2 divisors, whose sum is σ = 1130494440462. Its totient is φ = 1130494440460.
The previous prime is 1130494440407. The next prime is 1130494440463. The reversal of 1130494440461 is 1640444940311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 947828809225 + 182665631236 = 973565^2 + 427394^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130494440461 is a prime.
Together with 1130494440463, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130494440463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565247220230 + 565247220231.
It is an arithmetic number, because the mean of its divisors is an integer number (565247220231).
Almost surely, 21130494440461 is an apocalyptic number.
It is an amenable number.
1130494440461 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130494440461 is an equidigital number, since it uses as much as digits as its factorization.
1130494440461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 41.
The spelling of 1130494440461 in words is "one trillion, one hundred thirty billion, four hundred ninety-four million, four hundred forty thousand, four hundred sixty-one".
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