113100031031231 has 2 divisors, whose sum is σ = 113100031031232. Its totient is φ = 113100031031230.

The previous prime is 113100031031177. The next prime is 113100031031233. The reversal of 113100031031231 is 132130130001311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113100031031231 is a prime.

It is a super-2 number, since 2×113100031031231² (a number of 29 digits) contains 22 as substring.

Together with 113100031031233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113100031031233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550015515615 + 56550015515616.

It is an arithmetic number, because the mean of its divisors is an integer number (56550015515616).

Almost surely, 2^{113100031031231} is an apocalyptic number.

113100031031231 is a deficient number, since it is larger than the sum of its proper divisors (1).

113100031031231 is an equidigital number, since it uses as much as digits as its factorization.

113100031031231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113100031031231 its reverse (132130130001311), we get a palindrome (245230161032542).

The spelling of 113100031031231 in words is "one hundred thirteen trillion, one hundred billion, thirty-one million, thirty-one thousand, two hundred thirty-one".