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11310033331123 is a prime number
BaseRepresentation
bin1010010010010101001010…
…0001001110001110110011
31111001020011200001201212221
42210211102201032032303
52440300422013043443
640015431345501511
72245060112052142
oct244452241161663
944036150051787
1011310033331123
113670615a663aa
121327b63341897
136406bab10387
142b15a1035759
151492eeb0beed
hexa495284e3b3

11310033331123 has 2 divisors, whose sum is σ = 11310033331124. Its totient is φ = 11310033331122.

The previous prime is 11310033331039. The next prime is 11310033331141. The reversal of 11310033331123 is 32113333001311.

It is a strong prime.

It is an emirp because it is prime and its reverse (32113333001311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310033331123 is a prime.

It is a super-2 number, since 2×113100333311232 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11310033331153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655016665561 + 5655016665562.

It is an arithmetic number, because the mean of its divisors is an integer number (5655016665562).

Almost surely, 211310033331123 is an apocalyptic number.

11310033331123 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310033331123 is an equidigital number, since it uses as much as digits as its factorization.

11310033331123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11310033331123 its reverse (32113333001311), we get a palindrome (43423366332434).

The spelling of 11310033331123 in words is "eleven trillion, three hundred ten billion, thirty-three million, three hundred thirty-one thousand, one hundred twenty-three".