Base | Representation |
---|---|
bin | 1110100110100111101111… |
… | …10011100101110001011111 |
3 | 11012201000010101120121002021 |
4 | 13103103313303211301133 |
5 | 13202121101222020221 |
6 | 152144354515441011 |
7 | 6523053220455562 |
oct | 723236763456137 |
9 | 135630111517067 |
10 | 32113333001311 |
11 | a261208317191 |
12 | 37279422b6167 |
13 | 14bc374868933 |
14 | 7d041794a4d9 |
15 | 3aa51c7c0041 |
hex | 1d34f7ce5c5f |
32113333001311 has 2 divisors, whose sum is σ = 32113333001312. Its totient is φ = 32113333001310.
The previous prime is 32113333001293. The next prime is 32113333001363. The reversal of 32113333001311 is 11310033331123.
It is a weak prime.
It is an emirp because it is prime and its reverse (11310033331123) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32113333001311 - 25 = 32113333001279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (32113333001381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16056666500655 + 16056666500656.
It is an arithmetic number, because the mean of its divisors is an integer number (16056666500656).
Almost surely, 232113333001311 is an apocalyptic number.
32113333001311 is a deficient number, since it is larger than the sum of its proper divisors (1).
32113333001311 is an equidigital number, since it uses as much as digits as its factorization.
32113333001311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 32113333001311 its reverse (11310033331123), we get a palindrome (43423366332434).
The spelling of 32113333001311 in words is "thirty-two trillion, one hundred thirteen billion, three hundred thirty-three million, one thousand, three hundred eleven".
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