Base | Representation |
---|---|
bin | 110100101010101011… |
… | …0001100011100100001 |
3 | 101210221012112200110112 |
4 | 1221111112030130201 |
5 | 3323112330444301 |
6 | 123542523341105 |
7 | 11112514621514 |
oct | 1512526143441 |
9 | 353835480415 |
10 | 113101031201 |
11 | 43a69646814 |
12 | 19b05381795 |
13 | a885ac6402 |
14 | 568cda8d7b |
15 | 2e1e4969bb |
hex | 1a5558c721 |
113101031201 has 2 divisors, whose sum is σ = 113101031202. Its totient is φ = 113101031200.
The previous prime is 113101031189. The next prime is 113101031203. The reversal of 113101031201 is 102130101311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111790591201 + 1310440000 = 334351^2 + 36200^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113101031201 is a prime.
Together with 113101031203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (113101031203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550515600 + 56550515601.
It is an arithmetic number, because the mean of its divisors is an integer number (56550515601).
Almost surely, 2113101031201 is an apocalyptic number.
It is an amenable number.
113101031201 is a deficient number, since it is larger than the sum of its proper divisors (1).
113101031201 is an equidigital number, since it uses as much as digits as its factorization.
113101031201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 113101031201 its reverse (102130101311), we get a palindrome (215231132512).
The spelling of 113101031201 in words is "one hundred thirteen billion, one hundred one million, thirty-one thousand, two hundred one".
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