Base | Representation |
---|---|
bin | 110100101010101011… |
… | …0100000011110011111 |
3 | 101210221012200212000021 |
4 | 1221111112200132133 |
5 | 3323112341110442 |
6 | 123542525213011 |
7 | 11112515412643 |
oct | 1512526403637 |
9 | 353835625007 |
10 | 113101113247 |
11 | 43a696a2421 |
12 | 19b05401167 |
13 | a885b24865 |
14 | 568cdcac23 |
15 | 2e1e4b0e67 |
hex | 1a555a079f |
113101113247 has 2 divisors, whose sum is σ = 113101113248. Its totient is φ = 113101113246.
The previous prime is 113101113241. The next prime is 113101113259. The reversal of 113101113247 is 742311101311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113101113247 - 219 = 113100588959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113101113241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550556623 + 56550556624.
It is an arithmetic number, because the mean of its divisors is an integer number (56550556624).
Almost surely, 2113101113247 is an apocalyptic number.
113101113247 is a deficient number, since it is larger than the sum of its proper divisors (1).
113101113247 is an equidigital number, since it uses as much as digits as its factorization.
113101113247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 113101113247 its reverse (742311101311), we get a palindrome (855412214558).
The spelling of 113101113247 in words is "one hundred thirteen billion, one hundred one million, one hundred thirteen thousand, two hundred forty-seven".
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