1131011300330 has 64 divisors (see below), whose sum is σ = 2175871610880. Its totient is φ = 421793455104.

The previous prime is 1131011300327. The next prime is 1131011300357. The reversal of 1131011300330 is 330031101311.

It is a super-2 number, since 2×1131011300330² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1131011300299 and 1131011300308.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14188064 + ... + 14267556.

It is an arithmetic number, because the mean of its divisors is an integer number (33997993920).

Almost surely, 2^{1131011300330} is an apocalyptic number.

1131011300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131011300330 is a deficient number, since it is larger than the sum of its proper divisors (1044860310550).

1131011300330 is a wasteful number, since it uses less digits than its factorization.

1131011300330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80303.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1131011300330 its reverse (330031101311), we get a palindrome (1461042401641).

It can be divided in two parts, 1131011 and 300330, that added together give a palindrome (1431341).

The spelling of 1131011300330 in words is "one trillion, one hundred thirty-one billion, eleven million, three hundred thousand, three hundred thirty".