Base | Representation |
---|---|
bin | 10000011101010101100… |
… | …010001001110111010111 |
3 | 11000010100010111220100121 |
4 | 100131111202021313113 |
5 | 122012302410244021 |
6 | 2223325055452411 |
7 | 144466342260445 |
oct | 20352542116727 |
9 | 4003303456317 |
10 | 1131011415511 |
11 | 3a672850550a |
12 | 163245527107 |
13 | 82866876493 |
14 | 3ca53d91b95 |
15 | 1e6482b3741 |
hex | 10755889dd7 |
1131011415511 has 2 divisors, whose sum is σ = 1131011415512. Its totient is φ = 1131011415510.
The previous prime is 1131011415503. The next prime is 1131011415559. The reversal of 1131011415511 is 1155141101311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131011415511 - 23 = 1131011415503 is a prime.
It is a super-2 number, since 2×11310114155112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131011415581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565505707755 + 565505707756.
It is an arithmetic number, because the mean of its divisors is an integer number (565505707756).
Almost surely, 21131011415511 is an apocalyptic number.
1131011415511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131011415511 is an equidigital number, since it uses as much as digits as its factorization.
1131011415511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 300, while the sum is 25.
Adding to 1131011415511 its reverse (1155141101311), we get a palindrome (2286152516822).
The spelling of 1131011415511 in words is "one trillion, one hundred thirty-one billion, eleven million, four hundred fifteen thousand, five hundred eleven".
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