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11310123030343 is a prime number
BaseRepresentation
bin1010010010010101011111…
…0111011001011101000111
31111001020101220211221002021
42210211113313121131013
52440301112443432333
640015444312224011
72245062251352664
oct244452767313507
944036356757067
1011310123030343
113670661661795
121327b8939b007
13640703588437
142b15acd04a6b
1514930792982d
hexa4957dd9747

11310123030343 has 2 divisors, whose sum is σ = 11310123030344. Its totient is φ = 11310123030342.

The previous prime is 11310123030329. The next prime is 11310123030347. The reversal of 11310123030343 is 34303032101311.

It is a strong prime.

It is an emirp because it is prime and its reverse (34303032101311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310123030343 - 233 = 11301533095751 is a prime.

It is a super-2 number, since 2×113101230303432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310123030347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655061515171 + 5655061515172.

It is an arithmetic number, because the mean of its divisors is an integer number (5655061515172).

Almost surely, 211310123030343 is an apocalyptic number.

11310123030343 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310123030343 is an equidigital number, since it uses as much as digits as its factorization.

11310123030343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11310123030343 its reverse (34303032101311), we get a palindrome (45613155131654).

The spelling of 11310123030343 in words is "eleven trillion, three hundred ten billion, one hundred twenty-three million, thirty thousand, three hundred forty-three".