Base | Representation |
---|---|
bin | 10000011101010110000… |
… | …100001100101111001101 |
3 | 11000010100202022022200122 |
4 | 100131112010030233031 |
5 | 122012312201341143 |
6 | 2223330015034325 |
7 | 144466511161043 |
oct | 20352604145715 |
9 | 4003322268618 |
10 | 1131020340173 |
11 | 3a6732550769 |
12 | 16324850b9a5 |
13 | 8286867c749 |
14 | 3ca55236393 |
15 | 1e648e77c68 |
hex | 1075610cbcd |
1131020340173 has 2 divisors, whose sum is σ = 1131020340174. Its totient is φ = 1131020340172.
The previous prime is 1131020340059. The next prime is 1131020340209. The reversal of 1131020340173 is 3710430201311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1098800808169 + 32219532004 = 1048237^2 + 179498^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131020340173 - 212 = 1131020336077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131020342173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565510170086 + 565510170087.
It is an arithmetic number, because the mean of its divisors is an integer number (565510170087).
Almost surely, 21131020340173 is an apocalyptic number.
It is an amenable number.
1131020340173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131020340173 is an equidigital number, since it uses as much as digits as its factorization.
1131020340173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1131020340173 its reverse (3710430201311), we get a palindrome (4841450541484).
The spelling of 1131020340173 in words is "one trillion, one hundred thirty-one billion, twenty million, three hundred forty thousand, one hundred seventy-three".
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