Base | Representation |
---|---|
bin | 10101000100010010… |
… | …00010100011000111 |
3 | 1002012020011100220121 |
4 | 22202021002203013 |
5 | 141130403311234 |
6 | 5110145042411 |
7 | 550164140566 |
oct | 124211024307 |
9 | 32166140817 |
10 | 11310213319 |
11 | 4884358739 |
12 | 2237926407 |
13 | 10b3290122 |
14 | 794181bdd |
15 | 462e194b4 |
hex | 2a22428c7 |
11310213319 has 2 divisors, whose sum is σ = 11310213320. Its totient is φ = 11310213318.
The previous prime is 11310213311. The next prime is 11310213323. The reversal of 11310213319 is 91331201311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11310213319 - 23 = 11310213311 is a prime.
It is a super-2 number, since 2×113102133192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11310213293 and 11310213302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310213311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655106659 + 5655106660.
It is an arithmetic number, because the mean of its divisors is an integer number (5655106660).
Almost surely, 211310213319 is an apocalyptic number.
11310213319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310213319 is an equidigital number, since it uses as much as digits as its factorization.
11310213319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 11310213319 in words is "eleven billion, three hundred ten million, two hundred thirteen thousand, three hundred nineteen".
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