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113102202181 is a prime number
BaseRepresentation
bin110100101010101101…
…0101010010101000101
3101210221021202011202011
41221111122222111011
53323113130432211
6123543004414221
711112530566453
oct1512532522505
9353837664664
10113102202181
1143a6a276571
1219b05847371
13a8861163b7
14568d1d19d3
152e1e628921
hex1a556aa545

113102202181 has 2 divisors, whose sum is σ = 113102202182. Its totient is φ = 113102202180.

The previous prime is 113102202179. The next prime is 113102202197. The reversal of 113102202181 is 181202201311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71080892100 + 42021310081 = 266610^2 + 204991^2 .

It is an emirp because it is prime and its reverse (181202201311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113102202181 - 21 = 113102202179 is a prime.

It is a super-2 number, since 2×1131022021812 (a number of 23 digits) contains 22 as substring.

Together with 113102202179, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113102202281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551101090 + 56551101091.

It is an arithmetic number, because the mean of its divisors is an integer number (56551101091).

Almost surely, 2113102202181 is an apocalyptic number.

It is an amenable number.

113102202181 is a deficient number, since it is larger than the sum of its proper divisors (1).

113102202181 is an equidigital number, since it uses as much as digits as its factorization.

113102202181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 113102202181 its reverse (181202201311), we get a palindrome (294304403492).

The spelling of 113102202181 in words is "one hundred thirteen billion, one hundred two million, two hundred two thousand, one hundred eighty-one".