11310222130213 has 2 divisors, whose sum is σ = 11310222130214. Its totient is φ = 11310222130212.

The previous prime is 11310222130211. The next prime is 11310222130243. The reversal of 11310222130213 is 31203122201311.

11310222130213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11131785163489 + 178436966724 = 3336433^2 + 422418^2 .

It is an emirp because it is prime and its reverse (31203122201311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310222130213 - 2¹ = 11310222130211 is a prime.

It is a super-2 number, since 2×11310222130213² (a number of 27 digits) contains 22 as substring.

Together with 11310222130211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310222130211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655111065106 + 5655111065107.

It is an arithmetic number, because the mean of its divisors is an integer number (5655111065107).

Almost surely, 2^{11310222130213} is an apocalyptic number.

It is an amenable number.

11310222130213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310222130213 is an equidigital number, since it uses as much as digits as its factorization.

11310222130213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11310222130213 its reverse (31203122201311), we get a palindrome (42513344331524).

The spelling of 11310222130213 in words is "eleven trillion, three hundred ten billion, two hundred twenty-two million, one hundred thirty thousand, two hundred thirteen".