Base | Representation |
---|---|
bin | 10000011101010110001… |
… | …011011100100100011011 |
3 | 11000010100212212211210121 |
4 | 100131112023130210123 |
5 | 122012313143140102 |
6 | 2223330123454111 |
7 | 144466533263011 |
oct | 20352613344433 |
9 | 4003325784717 |
10 | 1131022240027 |
11 | 3a6733629099 |
12 | 163249087337 |
13 | 82868b96414 |
14 | 3ca555ac8b1 |
15 | 1e649200b37 |
hex | 107562dc91b |
1131022240027 has 2 divisors, whose sum is σ = 1131022240028. Its totient is φ = 1131022240026.
The previous prime is 1131022240003. The next prime is 1131022240031. The reversal of 1131022240027 is 7200422201311.
It is a strong prime.
It is an emirp because it is prime and its reverse (7200422201311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131022240027 - 219 = 1131021715739 is a prime.
It is a super-2 number, since 2×11310222400272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131022239983 and 1131022240010.
It is not a weakly prime, because it can be changed into another prime (1131022240067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565511120013 + 565511120014.
It is an arithmetic number, because the mean of its divisors is an integer number (565511120014).
Almost surely, 21131022240027 is an apocalyptic number.
1131022240027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131022240027 is an equidigital number, since it uses as much as digits as its factorization.
1131022240027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1131022240027 its reverse (7200422201311), we get a palindrome (8331444441338).
The spelling of 1131022240027 in words is "one trillion, one hundred thirty-one billion, twenty-two million, two hundred forty thousand, twenty-seven".
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