Base | Representation |
---|---|
bin | 10000011101010110001… |
… | …011011100100100000011 |
3 | 11000010100212212211202201 |
4 | 100131112023130210003 |
5 | 122012313143140003 |
6 | 2223330123454031 |
7 | 144466533262645 |
oct | 20352613344403 |
9 | 4003325784681 |
10 | 1131022240003 |
11 | 3a6733629077 |
12 | 163249087317 |
13 | 82868b963c6 |
14 | 3ca555ac895 |
15 | 1e649200b1d |
hex | 107562dc903 |
1131022240003 has 2 divisors, whose sum is σ = 1131022240004. Its totient is φ = 1131022240002.
The previous prime is 1131022240001. The next prime is 1131022240027. The reversal of 1131022240003 is 3000422201311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131022240003 - 21 = 1131022240001 is a prime.
It is a super-2 number, since 2×11310222400032 (a number of 25 digits) contains 22 as substring.
Together with 1131022240001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1131022240001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565511120001 + 565511120002.
It is an arithmetic number, because the mean of its divisors is an integer number (565511120002).
Almost surely, 21131022240003 is an apocalyptic number.
1131022240003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131022240003 is an equidigital number, since it uses as much as digits as its factorization.
1131022240003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 1131022240003 its reverse (3000422201311), we get a palindrome (4131444441314).
The spelling of 1131022240003 in words is "one trillion, one hundred thirty-one billion, twenty-two million, two hundred forty thousand, three".
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