113103013147 has 2 divisors, whose sum is σ = 113103013148. Its totient is φ = 113103013146.

The previous prime is 113103013139. The next prime is 113103013151. The reversal of 113103013147 is 741310301311.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (741310301311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113103013147 - 2³ = 113103013139 is a prime.

It is not a weakly prime, because it can be changed into another prime (113103013847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551506573 + 56551506574.

It is an arithmetic number, because the mean of its divisors is an integer number (56551506574).

Almost surely, 2^113103013147 is an apocalyptic number.

113103013147 is a deficient number, since it is larger than the sum of its proper divisors (1).

113103013147 is an equidigital number, since it uses as much as digits as its factorization.

113103013147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 113103013147 its reverse (741310301311), we get a palindrome (854413314458).

The spelling of 113103013147 in words is "one hundred thirteen billion, one hundred three million, thirteen thousand, one hundred forty-seven".