Search a number
-
+
113103035413 is a prime number
BaseRepresentation
bin110100101010101110…
…1110101110000010101
3101210221100022111201121
41221111131311300111
53323113334113123
6123543034323541
711112540636634
oct1512535656025
9353840274647
10113103035413
1143a6a795595
1219b05b895b1
13a886348734
14568d36b51b
152e1e74075d
hex1a55775c15

113103035413 has 2 divisors, whose sum is σ = 113103035414. Its totient is φ = 113103035412.

The previous prime is 113103035369. The next prime is 113103035431. The reversal of 113103035413 is 314530301311.

Together with next prime (113103035431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106167143889 + 6935891524 = 325833^2 + 83282^2 .

It is a cyclic number.

It is not a de Polignac number, because 113103035413 - 225 = 113069480981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113103035473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56551517706 + 56551517707.

It is an arithmetic number, because the mean of its divisors is an integer number (56551517707).

Almost surely, 2113103035413 is an apocalyptic number.

It is an amenable number.

113103035413 is a deficient number, since it is larger than the sum of its proper divisors (1).

113103035413 is an equidigital number, since it uses as much as digits as its factorization.

113103035413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 113103035413 its reverse (314530301311), we get a palindrome (427633336724).

The spelling of 113103035413 in words is "one hundred thirteen billion, one hundred three million, thirty-five thousand, four hundred thirteen".