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11310332002133 is a prime number
BaseRepresentation
bin1010010010010110010001…
…0100100011111101010101
31111001020221111001210111012
42210211210110203331111
52440302024443032013
640015521135222005
72245100366525123
oct244454424437525
944036844053435
1011310332002133
11367075961234a
121328027377905
13640737964298
142b15cc980913
1514931ae571a8
hexa4964523f55

11310332002133 has 2 divisors, whose sum is σ = 11310332002134. Its totient is φ = 11310332002132.

The previous prime is 11310332002127. The next prime is 11310332002169. The reversal of 11310332002133 is 33120023301311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8081636923684 + 3228695078449 = 2842822^2 + 1796857^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310332002133 - 214 = 11310331985749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11310332002099 and 11310332002108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11310332002033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655166001066 + 5655166001067.

It is an arithmetic number, because the mean of its divisors is an integer number (5655166001067).

Almost surely, 211310332002133 is an apocalyptic number.

It is an amenable number.

11310332002133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310332002133 is an equidigital number, since it uses as much as digits as its factorization.

11310332002133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 11310332002133 its reverse (33120023301311), we get a palindrome (44430355303444).

The spelling of 11310332002133 in words is "eleven trillion, three hundred ten billion, three hundred thirty-two million, two thousand, one hundred thirty-three".