Base | Representation |
---|---|
bin | 1010010010010110010001… |
… | …1001000111001011100101 |
3 | 1111001020221120022101202202 |
4 | 2210211210121013023211 |
5 | 2440302030244214411 |
6 | 40015521220544245 |
7 | 2245100412623612 |
oct | 244454431071345 |
9 | 44036846271682 |
10 | 11310333194981 |
11 | 367075a257577 |
12 | 1328027852085 |
13 | 640737c91202 |
14 | 2b15ccbb1509 |
15 | 14931b0e083b |
hex | a49646472e5 |
11310333194981 has 2 divisors, whose sum is σ = 11310333194982. Its totient is φ = 11310333194980.
The previous prime is 11310333194971. The next prime is 11310333195013. The reversal of 11310333194981 is 18949133301311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8831393158756 + 2478940036225 = 2971766^2 + 1574465^2 .
It is a cyclic number.
It is not a de Polignac number, because 11310333194981 - 26 = 11310333194917 is a prime.
It is a super-2 number, since 2×113103331949812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310333194921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655166597490 + 5655166597491.
It is an arithmetic number, because the mean of its divisors is an integer number (5655166597491).
Almost surely, 211310333194981 is an apocalyptic number.
It is an amenable number.
11310333194981 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310333194981 is an equidigital number, since it uses as much as digits as its factorization.
11310333194981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 47.
The spelling of 11310333194981 in words is "eleven trillion, three hundred ten billion, three hundred thirty-three million, one hundred ninety-four thousand, nine hundred eighty-one".
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