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11310414130 = 251131041413
BaseRepresentation
bin10101000100010011…
…10011100100110010
31002012020112120101001
422202021303210302
5141130431223010
65110153232214
7550165635211
oct124211634462
932166476331
1011310414130
1148844855a4
122237a0266a
1310b3330652
147941d5078
15462e58c3a
hex2a2273932

11310414130 has 8 divisors (see below), whose sum is σ = 20358745452. Its totient is φ = 4524165648.

The previous prime is 11310414127. The next prime is 11310414131. The reversal of 11310414130 is 3141401311.

It can be written as a sum of positive squares in 2 ways, for example, as 10989538561 + 320875569 = 104831^2 + 17913^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11310414098 and 11310414107.

It is not an unprimeable number, because it can be changed into a prime (11310414131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565520697 + ... + 565520716.

Almost surely, 211310414130 is an apocalyptic number.

11310414130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11310414130 is a deficient number, since it is larger than the sum of its proper divisors (9048331322).

11310414130 is a wasteful number, since it uses less digits than its factorization.

11310414130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1131041420.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 11310414130 its reverse (3141401311), we get a palindrome (14451815441).

The spelling of 11310414130 in words is "eleven billion, three hundred ten million, four hundred fourteen thousand, one hundred thirty".

Divisors: 1 2 5 10 1131041413 2262082826 5655207065 11310414130