Base | Representation |
---|---|
bin | 10101000100010011… |
… | …10011100100101111 |
3 | 1002012020112120100221 |
4 | 22202021303210233 |
5 | 141130431223002 |
6 | 5110153232211 |
7 | 550165635205 |
oct | 124211634457 |
9 | 32166476327 |
10 | 11310414127 |
11 | 48844855a1 |
12 | 2237a02667 |
13 | 10b333064c |
14 | 7941d5075 |
15 | 462e58c37 |
hex | 2a227392f |
11310414127 has 2 divisors, whose sum is σ = 11310414128. Its totient is φ = 11310414126.
The previous prime is 11310414113. The next prime is 11310414131. The reversal of 11310414127 is 72141401311.
11310414127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11310414127 - 231 = 9162930479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310414527) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655207063 + 5655207064.
It is an arithmetic number, because the mean of its divisors is an integer number (5655207064).
Almost surely, 211310414127 is an apocalyptic number.
11310414127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310414127 is an equidigital number, since it uses as much as digits as its factorization.
11310414127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 11310414127 its reverse (72141401311), we get a palindrome (83451815438).
The spelling of 11310414127 in words is "eleven billion, three hundred ten million, four hundred fourteen thousand, one hundred twenty-seven".
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