Base | Representation |
---|---|
bin | 1010010010010110100110… |
… | …1001100110010110001111 |
3 | 1111001021011201021211110021 |
4 | 2210211221221212112033 |
5 | 2440302220334344043 |
6 | 40015534051323011 |
7 | 2245102533444121 |
oct | 244455151462617 |
9 | 44037151254407 |
10 | 11310421403023 |
11 | 36707a5024586 |
12 | 13280512b0467 |
13 | 640750336612 |
14 | 2b15da7b3211 |
15 | 149323c163ed |
hex | a4969a6658f |
11310421403023 has 2 divisors, whose sum is σ = 11310421403024. Its totient is φ = 11310421403022.
The previous prime is 11310421403009. The next prime is 11310421403033. The reversal of 11310421403023 is 32030412401311.
11310421403023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11310421403023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11310421403033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655210701511 + 5655210701512.
It is an arithmetic number, because the mean of its divisors is an integer number (5655210701512).
Almost surely, 211310421403023 is an apocalyptic number.
11310421403023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11310421403023 is an equidigital number, since it uses as much as digits as its factorization.
11310421403023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11310421403023 its reverse (32030412401311), we get a palindrome (43340833804334).
The spelling of 11310421403023 in words is "eleven trillion, three hundred ten billion, four hundred twenty-one million, four hundred three thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •