Base | Representation |
---|---|
bin | 11001101101111000100101… |
… | …101001001101010001000111 |
3 | 112211110122222011021220110021 |
4 | 121231320211221031101013 |
5 | 104311100101341111403 |
6 | 1040315222005240011 |
7 | 32552342000130553 |
oct | 3155704551152107 |
9 | 484418864256407 |
10 | 113104300332103 |
11 | 3304729aa07143 |
12 | 10828455403007 |
13 | 4b158c75184b2 |
14 | 1dd03c506a863 |
15 | d1218098d8bd |
hex | 66de25a4d447 |
113104300332103 has 2 divisors, whose sum is σ = 113104300332104. Its totient is φ = 113104300332102.
The previous prime is 113104300332091. The next prime is 113104300332131. The reversal of 113104300332103 is 301233003401311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113104300332103 is a prime.
It is a super-2 number, since 2×1131043003321032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113104300332403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56552150166051 + 56552150166052.
It is an arithmetic number, because the mean of its divisors is an integer number (56552150166052).
Almost surely, 2113104300332103 is an apocalyptic number.
113104300332103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113104300332103 is an equidigital number, since it uses as much as digits as its factorization.
113104300332103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 113104300332103 its reverse (301233003401311), we get a palindrome (414337303733414).
The spelling of 113104300332103 in words is "one hundred thirteen trillion, one hundred four billion, three hundred million, three hundred thirty-two thousand, one hundred three".
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