11311010227631 has 2 divisors, whose sum is σ = 11311010227632. Its totient is φ = 11311010227630.

The previous prime is 11311010227571. The next prime is 11311010227633. The reversal of 11311010227631 is 13672201011311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11311010227631 is a prime.

It is a super-2 number, since 2×11311010227631² (a number of 27 digits) contains 22 as substring.

Together with 11311010227633, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311010227594 and 11311010227603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311010227633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655505113815 + 5655505113816.

It is an arithmetic number, because the mean of its divisors is an integer number (5655505113816).

Almost surely, 2^{11311010227631} is an apocalyptic number.

11311010227631 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311010227631 is an equidigital number, since it uses as much as digits as its factorization.

11311010227631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 29.

Adding to 11311010227631 its reverse (13672201011311), we get a palindrome (24983211238942).

The spelling of 11311010227631 in words is "eleven trillion, three hundred eleven billion, ten million, two hundred twenty-seven thousand, six hundred thirty-one".