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113110154431 is a prime number
BaseRepresentation
bin110100101010111100…
…0111111110010111111
3101210221211201012011221
41221111320333302333
53323122144420211
6123543451054211
711112655310041
oct1512570776277
9353854635157
10113110154431
1143a7380817a
1219b08441367
13a88796bb81
1456902a1a91
152e20199c71
hex1a55e3fcbf

113110154431 has 2 divisors, whose sum is σ = 113110154432. Its totient is φ = 113110154430.

The previous prime is 113110154407. The next prime is 113110154459. The reversal of 113110154431 is 134451011311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113110154431 - 27 = 113110154303 is a prime.

It is a super-2 number, since 2×1131101544312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113110154396 and 113110154405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113110152431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56555077215 + 56555077216.

It is an arithmetic number, because the mean of its divisors is an integer number (56555077216).

Almost surely, 2113110154431 is an apocalyptic number.

113110154431 is a deficient number, since it is larger than the sum of its proper divisors (1).

113110154431 is an equidigital number, since it uses as much as digits as its factorization.

113110154431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 113110154431 its reverse (134451011311), we get a palindrome (247561165742).

The spelling of 113110154431 in words is "one hundred thirteen billion, one hundred ten million, one hundred fifty-four thousand, four hundred thirty-one".