Base | Representation |
---|---|
bin | 1010010010011001001011… |
… | …0001011100001010110111 |
3 | 1111001022221210111110120202 |
4 | 2210212102301130022313 |
5 | 2440310123444334333 |
6 | 40020130334551115 |
7 | 2245125611620415 |
oct | 244462261341267 |
9 | 44038853443522 |
10 | 11311111324343 |
11 | 367101950a696 |
12 | 132820436849b |
13 | 64083025739c |
14 | 2b16642862b5 |
15 | 1493645975e8 |
hex | a4992c5c2b7 |
11311111324343 has 2 divisors, whose sum is σ = 11311111324344. Its totient is φ = 11311111324342.
The previous prime is 11311111324333. The next prime is 11311111324351. The reversal of 11311111324343 is 34342311111311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311111324343 - 24 = 11311111324327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311111324333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655555662171 + 5655555662172.
It is an arithmetic number, because the mean of its divisors is an integer number (5655555662172).
Almost surely, 211311111324343 is an apocalyptic number.
11311111324343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311111324343 is an equidigital number, since it uses as much as digits as its factorization.
11311111324343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 29.
Adding to 11311111324343 its reverse (34342311111311), we get a palindrome (45653422435654).
The spelling of 11311111324343 in words is "eleven trillion, three hundred eleven billion, one hundred eleven million, three hundred twenty-four thousand, three hundred forty-three".
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