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11311131221023 is a prime number
BaseRepresentation
bin1010010010011001001111…
…1101010101110000011111
31111001100000011221022200211
42210212103331111300133
52440310144043033043
640020132325233251
72245126243006264
oct244462375256037
944040004838624
1011311131221023
11367102976a327
12132820ab62827
1364083440277a
142b1666b8526b
151493661c7a9d
hexa4993f55c1f

11311131221023 has 2 divisors, whose sum is σ = 11311131221024. Its totient is φ = 11311131221022.

The previous prime is 11311131221021. The next prime is 11311131221107. The reversal of 11311131221023 is 32012213111311.

It is a weak prime.

It is an emirp because it is prime and its reverse (32012213111311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11311131221023 - 21 = 11311131221021 is a prime.

Together with 11311131221021, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11311131220985 and 11311131221003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311131221021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655565610511 + 5655565610512.

It is an arithmetic number, because the mean of its divisors is an integer number (5655565610512).

Almost surely, 211311131221023 is an apocalyptic number.

11311131221023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311131221023 is an equidigital number, since it uses as much as digits as its factorization.

11311131221023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 11311131221023 its reverse (32012213111311), we get a palindrome (43323344332334).

The spelling of 11311131221023 in words is "eleven trillion, three hundred eleven billion, one hundred thirty-one million, two hundred twenty-one thousand, twenty-three".