Base | Representation |
---|---|
bin | 10000011101011011100… |
… | …110100001001111010111 |
3 | 11000010121020002021011001 |
4 | 100131123212201033113 |
5 | 122013004441120002 |
6 | 2223343133524131 |
7 | 144502016521606 |
oct | 20353346411727 |
9 | 4003536067131 |
10 | 1131113223127 |
11 | 3a677aa21038 |
12 | 163273643647 |
13 | 828819a0984 |
14 | 3ca636d3a3d |
15 | 1e6521c3a87 |
hex | 1075b9a13d7 |
1131113223127 has 2 divisors, whose sum is σ = 1131113223128. Its totient is φ = 1131113223126.
The previous prime is 1131113223109. The next prime is 1131113223173. The reversal of 1131113223127 is 7213223111311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131113223127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131113223095 and 1131113223104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131113233127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565556611563 + 565556611564.
It is an arithmetic number, because the mean of its divisors is an integer number (565556611564).
Almost surely, 21131113223127 is an apocalyptic number.
1131113223127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131113223127 is an equidigital number, since it uses as much as digits as its factorization.
1131113223127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1512, while the sum is 28.
Adding to 1131113223127 its reverse (7213223111311), we get a palindrome (8344336334438).
The spelling of 1131113223127 in words is "one trillion, one hundred thirty-one billion, one hundred thirteen million, two hundred twenty-three thousand, one hundred twenty-seven".
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