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1131121300349 is a prime number
BaseRepresentation
bin10000011101011100000…
…101010101001101111101
311000010121210021122000102
4100131130011111031331
5122013014023102344
62223344023010445
7144502145262425
oct20353405251575
94003553248012
101131121300349
113a6784538627
12163276299a25
138288356b2b1
143ca647d7485
151e652c6be4e
hex1075c15537d

1131121300349 has 2 divisors, whose sum is σ = 1131121300350. Its totient is φ = 1131121300348.

The previous prime is 1131121300319. The next prime is 1131121300369. The reversal of 1131121300349 is 9430031211311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1030620888025 + 100500412324 = 1015195^2 + 317018^2 .

It is an emirp because it is prime and its reverse (9430031211311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131121300349 - 216 = 1131121234813 is a prime.

It is a super-2 number, since 2×11311213003492 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131121300319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565560650174 + 565560650175.

It is an arithmetic number, because the mean of its divisors is an integer number (565560650175).

Almost surely, 21131121300349 is an apocalyptic number.

It is an amenable number.

1131121300349 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131121300349 is an equidigital number, since it uses as much as digits as its factorization.

1131121300349 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 1131121300349 in words is "one trillion, one hundred thirty-one billion, one hundred twenty-one million, three hundred thousand, three hundred forty-nine".