113113030223 has 2 divisors, whose sum is σ = 113113030224. Its totient is φ = 113113030222.

The previous prime is 113113030189. The next prime is 113113030243. The reversal of 113113030223 is 322030311311.

It is an a-pointer prime, because the next prime (113113030243) can be obtained adding 113113030223 to its sum of digits (20).

It is a strong prime.

It is an emirp because it is prime and its reverse (322030311311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113113030223 - 2¹⁰ = 113113029199 is a prime.

It is a super-2 number, since 2×113113030223² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113113030195 and 113113030204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113113030243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556515111 + 56556515112.

It is an arithmetic number, because the mean of its divisors is an integer number (56556515112).

Almost surely, 2^113113030223 is an apocalyptic number.

113113030223 is a deficient number, since it is larger than the sum of its proper divisors (1).

113113030223 is an equidigital number, since it uses as much as digits as its factorization.

113113030223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 113113030223 its reverse (322030311311), we get a palindrome (435143341534).

The spelling of 113113030223 in words is "one hundred thirteen billion, one hundred thirteen million, thirty thousand, two hundred twenty-three".