Base | Representation |
---|---|
bin | 10101000100011010… |
… | …01100100110111111 |
3 | 1002012022012201210222 |
4 | 22202031030212333 |
5 | 141131143144403 |
6 | 5110224251555 |
7 | 550206330032 |
oct | 124215144677 |
9 | 32168181728 |
10 | 11311303103 |
11 | 4884a32491 |
12 | 2238170bbb |
13 | 10b3582179 |
14 | 794387019 |
15 | 463082338 |
hex | 2a234c9bf |
11311303103 has 2 divisors, whose sum is σ = 11311303104. Its totient is φ = 11311303102.
The previous prime is 11311303063. The next prime is 11311303109. The reversal of 11311303103 is 30130311311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311303103 - 224 = 11294525887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311303109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655651551 + 5655651552.
It is an arithmetic number, because the mean of its divisors is an integer number (5655651552).
Almost surely, 211311303103 is an apocalyptic number.
11311303103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311303103 is an equidigital number, since it uses as much as digits as its factorization.
11311303103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11311303103 its reverse (30130311311), we get a palindrome (41441614414).
The spelling of 11311303103 in words is "eleven billion, three hundred eleven million, three hundred three thousand, one hundred three".
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