Base | Representation |
---|---|
bin | 11001101110000000111000… |
… | …101110000011010010101111 |
3 | 112211111111222002222100122221 |
4 | 121232000320232003102233 |
5 | 104311221323314204123 |
6 | 1040323254053020211 |
7 | 32553105540500203 |
oct | 3156007056032257 |
9 | 484444862870587 |
10 | 113113210303663 |
11 | 330500523a76a9 |
12 | 1082a121324667 |
13 | 4b166b743690b |
14 | 1dd09cc528b03 |
15 | d12502cd525d |
hex | 66e038b834af |
113113210303663 has 2 divisors, whose sum is σ = 113113210303664. Its totient is φ = 113113210303662.
The previous prime is 113113210303657. The next prime is 113113210303673. The reversal of 113113210303663 is 366303012311311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113113210303663 - 221 = 113113208206511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113113210303673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56556605151831 + 56556605151832.
It is an arithmetic number, because the mean of its divisors is an integer number (56556605151832).
Almost surely, 2113113210303663 is an apocalyptic number.
113113210303663 is a deficient number, since it is larger than the sum of its proper divisors (1).
113113210303663 is an equidigital number, since it uses as much as digits as its factorization.
113113210303663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 34.
Adding to 113113210303663 its reverse (366303012311311), we get a palindrome (479416222614974).
The spelling of 113113210303663 in words is "one hundred thirteen trillion, one hundred thirteen billion, two hundred ten million, three hundred three thousand, six hundred sixty-three".
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