Base | Representation |
---|---|
bin | 10000011101011100110… |
… | …011001100000001010111 |
3 | 11000010122121220100122221 |
4 | 100131130303030001113 |
5 | 122013030112240203 |
6 | 2223345132403211 |
7 | 144502352410066 |
oct | 20353463140127 |
9 | 4003577810587 |
10 | 1131133321303 |
11 | 3a67902a90a7 |
12 | 16327a316507 |
13 | 82885bb999b |
14 | 3ca662461dd |
15 | 1e653d43abd |
hex | 1075cccc057 |
1131133321303 has 2 divisors, whose sum is σ = 1131133321304. Its totient is φ = 1131133321302.
The previous prime is 1131133321229. The next prime is 1131133321309. The reversal of 1131133321303 is 3031233311311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131133321303 - 29 = 1131133320791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131133321309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565566660651 + 565566660652.
It is an arithmetic number, because the mean of its divisors is an integer number (565566660652).
Almost surely, 21131133321303 is an apocalyptic number.
1131133321303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131133321303 is an equidigital number, since it uses as much as digits as its factorization.
1131133321303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 1131133321303 its reverse (3031233311311), we get a palindrome (4162366632614).
The spelling of 1131133321303 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-three million, three hundred twenty-one thousand, three hundred three".
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