Base | Representation |
---|---|
bin | 110100101011000100… |
… | …0001110000101101010 |
3 | 101210222010012221101121 |
4 | 1221112020032011222 |
5 | 3323124210121010 |
6 | 123544112405454 |
7 | 11113034240530 |
oct | 1512610160552 |
9 | 353863187347 |
10 | 113114145130 |
11 | 43a75a93478 |
12 | 19b0984688a |
13 | a88873842c |
14 | 5690a20150 |
15 | 2e206d73da |
hex | 1a5620e16a |
113114145130 has 64 divisors (see below), whose sum is σ = 242875957248. Its totient is φ = 37085590080.
The previous prime is 113114145113. The next prime is 113114145143. The reversal of 113114145130 is 31541411311.
It is a junction number, because it is equal to n+sod(n) for n = 113114145095 and 113114145104.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7770639 + ... + 7785181.
It is an arithmetic number, because the mean of its divisors is an integer number (3794936832).
Almost surely, 2113114145130 is an apocalyptic number.
113114145130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113114145130 is an abundant number, since it is smaller than the sum of its proper divisors (129761812118).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113114145130 is a wasteful number, since it uses less digits than its factorization.
113114145130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19411.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 113114145130 its reverse (31541411311), we get a palindrome (144655556441).
The spelling of 113114145130 in words is "one hundred thirteen billion, one hundred fourteen million, one hundred forty-five thousand, one hundred thirty".
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