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11312003147 is a prime number
BaseRepresentation
bin10101000100011111…
…10111100001001011
31002012100112022002112
422202033313201023
5141131333100042
65110251252535
7550215304004
oct124217674113
932170468075
1011312003147
114885370435
12223844a14b
1310b37689b3
147944ca1ab
1546316e982
hex2a23f784b

11312003147 has 2 divisors, whose sum is σ = 11312003148. Its totient is φ = 11312003146.

The previous prime is 11312003069. The next prime is 11312003149. The reversal of 11312003147 is 74130021311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11312003147 - 218 = 11311741003 is a prime.

It is a super-2 number, since 2×113120031472 (a number of 21 digits) contains 22 as substring.

Together with 11312003149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11312003149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656001573 + 5656001574.

It is an arithmetic number, because the mean of its divisors is an integer number (5656001574).

Almost surely, 211312003147 is an apocalyptic number.

11312003147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312003147 is an equidigital number, since it uses as much as digits as its factorization.

11312003147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 11312003147 its reverse (74130021311), we get a palindrome (85442024458).

The spelling of 11312003147 in words is "eleven billion, three hundred twelve million, three thousand, one hundred forty-seven".