11312004041130 has 64 divisors (see below), whose sum is σ = 29287851280128. Its totient is φ = 2779667435520.

The previous prime is 11312004041081. The next prime is 11312004041161. The reversal of 11312004041130 is 3114040021311.

It is a super-2 number, since 2×11312004041130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11312004041097 and 11312004041106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24909406 + ... + 25359465.

It is an arithmetic number, because the mean of its divisors is an integer number (457622676252).

Almost surely, 2^{11312004041130} is an apocalyptic number.

11312004041130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11312004041130 is an abundant number, since it is smaller than the sum of its proper divisors (17975847238998).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11312004041130 is a wasteful number, since it uses less digits than its factorization.

11312004041130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50269471.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 11312004041130 its reverse (3114040021311), we get a palindrome (14426044062441).

The spelling of 11312004041130 in words is "eleven trillion, three hundred twelve billion, four million, forty-one thousand, one hundred thirty".