Base | Representation |
---|---|
bin | 110100101011010001… |
… | …0011010110100100110 |
3 | 101210222121010212101021 |
4 | 1221112202122310212 |
5 | 3323132434404110 |
6 | 123544515521354 |
7 | 11113146513544 |
oct | 1512642326446 |
9 | 353877125337 |
10 | 113121013030 |
11 | 43a79954423 |
12 | 19b0bbb925a |
13 | a889ca148c |
14 | 56918cad94 |
15 | 2e210e22da |
hex | 1a5689ad26 |
113121013030 has 64 divisors (see below), whose sum is σ = 207126885888. Its totient is φ = 44476441600.
The previous prime is 113121013021. The next prime is 113121013037. The reversal of 113121013030 is 30310121311.
It is a super-3 number, since 3×1131210130303 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113121012995 and 113121013013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113121013037) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 131078379 + ... + 131079241.
It is an arithmetic number, because the mean of its divisors is an integer number (3236357592).
Almost surely, 2113121013030 is an apocalyptic number.
113121013030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113121013030 is a deficient number, since it is larger than the sum of its proper divisors (94005872858).
113121013030 is a wasteful number, since it uses less digits than its factorization.
113121013030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1761.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 113121013030 its reverse (30310121311), we get a palindrome (143431134341).
The spelling of 113121013030 in words is "one hundred thirteen billion, one hundred twenty-one million, thirteen thousand, thirty".
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