Base | Representation |
---|---|
bin | 10101000100100000… |
… | …01111111101001111 |
3 | 1002012100201101101221 |
4 | 22202100033331033 |
5 | 141131344300442 |
6 | 5110253344211 |
7 | 550216201564 |
oct | 124220177517 |
9 | 32170641357 |
10 | 11312103247 |
11 | 4885429665 |
12 | 2238498067 |
13 | 10b37a2423 |
14 | 79451486b |
15 | 46318e467 |
hex | 2a240ff4f |
11312103247 has 2 divisors, whose sum is σ = 11312103248. Its totient is φ = 11312103246.
The previous prime is 11312103221. The next prime is 11312103251. The reversal of 11312103247 is 74230121311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11312103247 - 215 = 11312070479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11312103347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656051623 + 5656051624.
It is an arithmetic number, because the mean of its divisors is an integer number (5656051624).
Almost surely, 211312103247 is an apocalyptic number.
11312103247 is a deficient number, since it is larger than the sum of its proper divisors (1).
11312103247 is an equidigital number, since it uses as much as digits as its factorization.
11312103247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11312103247 its reverse (74230121311), we get a palindrome (85542224558).
The spelling of 11312103247 in words is "eleven billion, three hundred twelve million, one hundred three thousand, two hundred forty-seven".
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